10, 18, 20 Years Double Increment of West Bengal School Teachers, Staff Government Employee

10 years, 18 years and 20 years double increment / extra increment for West Bengal Government Employee / School Teachers & Staff.

In calculation ‘ *’  denote multiply and   ‘/’ denote divide.

1. Double Increment for 10 years, 20 years on 1st July

Formula

Late Basic Pay on June = b, After first increment basic  = f,  Basic of July after double increment =B

Then,  f = b*103/100  if it is multiple of 10 else f will be next multiple of 10.

After double increment, final basic [B] = f*103/100   if it is multiple of 10 else B will be next multiple of 10.

Example: 

Let for 10 years double increment in July 2017, Basic Pay of June, b =  20860, Grade Pay, g= 4800

Step1Then 20860*103/100 = 21485.50 => 21490 [next multiple of 10] = Basic after first increment [f]

Step2Now 21490*103/100 = 22134.70 => 22140 [next multiple of 10] =Final Basic[B]

So final basic after double increment = 22140

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2.  10 years, 20 years Increment  on any day from 2nd July to 31st July

Formula

Late Basic Pay on June = b, After first increment basic  = f,  Basic of July after double increment =B

Date (day) of this month is d, Number days of the month, N =31.

Basic of July after double increment =B

Then,  f = b*103/100  if it is multiple of 10 else f will be next multiple of 10.

F = f*103/100

B1 = f*(d – 1)/N    if it is multiple of 10 else B1 will be next multiple of 10.

B2 =  F*(N – d + 1)/N  if it is multiple of 10 else B2 will be next multiple of 10.

Final basic [B] = B1 + B2 .

Example : Let for 10 years  increment 18th July 2017, Basic Pay of June, b =  20860, Grade Pay, g= 4800

Then 20860*103/100 = 21485.50 => 21490 [next multiple of 10] = Basic after first increment [f]

F = 21490*103/100

B1  =>  21490*(18-1)/31 = 11784.83 =>11785  [rounded]

B2 =>(21490*103/100)*(31-18+1)/31  =9996.31 =>9996 [rounded]

Final basic = 11785+9996 = 21781

So Basic for July is 21781

Note:  It will not be rounded to next multiple of 10 for this [fraction] increment month.

Basic for next month August => 21490*(103/100) = 22134.70 => 22140 [next multiple of 10]

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3. 10 years, 20 years Increment  on any day from August to December

Formula
Late Basic Pay of previous month = b

Increment Date (day) of this month is d, Number days of the month =N,  [N = 30 or 31]

 

B1 = b*(d – 1)/N   [round in rupee]

B2 =  b*(103/100)*(N – d + 1)/N  [round in rupee]

Final basic [B] = B1 + B2 .

Example : Let for 10 years  increment 12th August 2017, Basic Pay of July, b = 21490, Grade Pay, g= 4800

For month of August total number of days, N = 31.

 

B1  =>  21490*(12-1)/31 =  7625.48 =>7625   [rounded]

B2 =>(21490*103/100)*(31-12+1)/31  =14280.45 =>14280 [rounded]

Final basic = 7626+14280 = 21905

So Basic for July is 21905 

Note:  It will not be rounded to next multiple of 10 for this [fraction] increment month.

Basic for next month  September => 21490*(103/100) = 22134.70 => 22140 [next multiple of 10]

Calculate yourself in http://www.biswa.net/salary-statement.html

4. 18 years double Increment for on 1st July

Note:  18 years extra increment facility is not available for all. As for example pass graduate teacher, Clerk, group etc can avail this facility but PG teachers will not.

In 18 years increment Grade Pay changes.

Formula: 

Late Basic Pay on June = b, After first increment basic  = f,  Basic of July after double increment =B,

Previous Grade Pay = g   and New Grade Pay = G

Then,  f = b*103/100  if it is multiple of 10 else f will be next multiple of 10.

B1 =  f*103/100 if it is multiple of 10 else B will be next multiple of 10.

After double increment, final basic [B] =B1 + G – g,

Example: 

Let for 18 years double increment in July 2017, Basic Pay of June, b =  24260,

Previous Grade Pay g= 4100;  New Grade Pay, G = 4400

Step1Then 24260*103/100 = 24987.80 => 24990 [next multiple of 10] = Basic after first increment [f]

Step2Now 24990*103/100 = 25739.70 => 25740 [next multiple of 10]

Step3:  Final Basic[B] = 25740 + (4400 – 4100) = 26040

So final basic after 18 years double increment = 26040

New Grade Pay 4400, Payband Pay = 26040 – 4400 = 21640

Calculate yourself in http://www.biswa.net/salary-statement.html

5. 18 years  Increment for on  2nd July to 31st July

Note:  18 years extra increment facility is not available for all. As for example pass graduate teacher, Clerk, group etc can avail this facility but PG teachers will not.

In 18 years increment Grade Pay changes.

Formula: 

Late Basic Pay on June = b, After first increment basic  = f,  Basic of July after double increment =B,

Previous Grade Pay = g   and New Grade Pay = G

Date of increment d , Total number of day in the month = N = 31

Then,  f = b*103/100  if it is multiple of 10 else f will be next multiple of 10.

F =  f*103/100

B1 = f*(d – 1)/N   [round in rupee]

B2 = F*(N – d + 1)/N

Final basic [B] =B1 + B2 + G – g,

 

Example: 

Let for 18 years  increment date is 22nd July 2017,  Basic Pay of June, b =  24260,

Previous Grade Pay g= 4100;  New Grade Pay, G = 4400

Step1f = 24260*103/100 = 24987.80 => 24990 [next multiple of 10] = Basic after first increment [f]

Step2F = 24990*103/100

Step3:  B1 = 24990*(22-1)/31 = 16928.70 => 16929 [rounded]

Step4: B2 = (24990*103/100)*(31 – 22 + 1)/31 = 8083.12 => 8083 [rounded]

Step5: Final Basic[B] = 16929 + 8083 + (4400 – 4100) = 25532

Note:  It will not be rounded to next multiple of 10 for this [fraction] increment month.

So final basic after 18 years double increment = 25532

New Grade Pay 4400, Payband Pay = 25532 – 4400 = 21132

New Basic pay for next Month August = (24990*103/100)  + (4400 – 4100)

= 25739.70 + 300  =26039.70 =>26040 [next multiple of 10]

Calculate yourself in http://www.biswa.net/salary-statement.html

6. 18 years  Increment for any day on  August to December

Note:  18 years extra increment facility is not available for all. As for example pass graduate teacher, Clerk, group etc can avail this facility but PG teachers will not.

In 18 years increment Grade Pay changes.

Formula: 

Late Basic Pay on Previous month = b,

Previous Grade Pay = g   and New Grade Pay = G

Date of increment d , Total number of day in the month = N,     [N = 30 or 31 according to month]

Then,  f = b*103/100  if it is multiple of 10 else f will be next multiple of 10.

 

B1 = b*(d – 1)/N   [round in rupee]

B2 = (b*103/100)*(N – d + 1)/N

Final basic [B] =B1 + B2 + G – g,

 

Example: 

Let for 18 years  increment date is 8th August 2017,  Basic Pay of July, b = 24990,

Previous Grade Pay g= 4100;  New Grade Pay, G = 4400

 

Step1:  B1 = 24990*(8-1)/31 = 5642.90 => 5643 [rounded]

Step4: B2 = (24990*103/100)*(31 – 8 + 1)/31 = 19927.50 => 19928 [rounded]

Step5: Final Basic[B] = 5643 + 19928 + (4400 – 4100) = 25871

Note:  It will not be rounded to next multiple of 10 for this [fraction] increment month.

So final basic in August after 18 years  increment = 25871

New Grade Pay 4400, Payband Pay = 25871 – 4400 = 21471

New Basic pay for next Month September = (24990*103/100)  + (4400 – 4100)

= 25739.70 + 300  =26039.70 =>26040 [next multiple of 10]

Calculate yourself in http://www.biswa.net/salary-statement.html

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Disclaimer:  This calculation gives no guaranty of 100% accuracy.

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